The point P is the two angle flat lines of △ ABC. Seeking corner A degree.

See the figure one as shown in the figure: In △ ABC, the angle flat division of BP and CP intersect at point P. If ∠BPC = 150 °, then ∠a = ______.

Hope
December 4, 2022 at 1:51 pm

0bpc = 150 °,
∴∠pbc ∠PCB = 180 ° -BPC = 180 ° -150 ° = 30 °,
n bABC ∠ACB = 2 (∠pbc ∠PCB) = 2 × 30 ° = 60 °,
In △ ABC, ∠a = 180 °- (∠ABC ∠ACB) = 180 ° -60 -60 ° = 120 °.
Therefore, the answer is: 120 °.

Reply